about di-66 project
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Hello Adel,
1) CTR = current transfer ratio = gain. A gain of 100% means 1 mA in LED side causes 1 mA in transistor side. A gain of 200% means 1 mA in LED = 2 mA in transistor.
Any CTR is ok but we recommend picking one with a specified range eg 100-200% so that you don't end up with variation in production - say 80% to 600%. Why? Well the CTR gain forms part of the overall loop gain so a narrower range makes it easy to ensure a good loop design over the range of opto CTR tolerance. I'd go for PC817B (the PC817 is likely to have a very wide CTR range).
2) Connect both in parallel ie both anodes together.
3) 12 V, 10 mA
4) ~5.8 V but you generally don't need to worry about the voltage on the pin
5) See datasheet but again don't generally need to consider this - unless I'm missing something you are trying to do.
6) Yes - but there are limits, for example both output must have some load to regulate correctly especially say if the 12 V is unloaded and 5 V is fully loaded.
7) No <10 uH is ok.
8) Also ok. Two resistors are normally required with using 0.25 W types due to voltage rating. Resistor see 375 V DC and 0.25 W = 350 V rating, 0.5 W = 500 V so single 0.5 W is ok but two 0.25 W needed. Interestingly I have heard of 0.25 W resistors failing in the field when only one was used (and therefore voltage rating was exceeded).
BTW take a look at the more detailed report:
http://www.powerint.com/sites/default/files/PDFFiles/der94.pdf
This is very close to the DI-066 design and has more complete design information.
Cheers
PI-Chekov
Hi Adel
1N4007G is glass passivated version of 1N4007. If you can't obtain then replace with FR106.
The LL4148 is just the SMD version of 1N4148 but any diode with trr <75 ns and >200 mA rating should be fine.
TOP246YN is lead free version of TOP246Y, other than that they are the same.
Good luck with your project.
Regards
Chekov